Bridge Rectifier
As nosotros know that the amount moving ridge rectifier is divided into 2 according amongst the break of pn diodes too the transformer used. One is the oculus tapped rectifier too the other is yoke rectifier. In this nosotros are going to come across almost the yoke rectifier.
CONSTRUCTION:
The yoke rectifer has the iv pn junction connected is a yoke mode thence it is named equally the yoke rectifer. Then it consists of the transformer, resistive charge too a capacitor for filtering the output moving ridge purpose.
CIRCUIT DIAGRAM:
WORKING:
As of the other rectifiers it has 2 working cycles i.e the positive too negative one-half cycles.
(i)DURING THE POSITIVE HALF CYCLE:
During the positive one-half wheel the diodes i too iii are inwards frontward bias status too thence the conduction takes house via the loop D1RLD3 thence output is obtained equally pulsating output for positive one-half cycle.
(ii)DURING THE NEGATIVE HALF CYCLE:
During the negative one-half wheel the diodes 2 too 4 deport because of the frontward bias status too the diodes i too iii rest inwards off patch due to the opposite bias condition. In this representative the electrical flow flows inwards the loop D4RLD2 thence the output is obtained equally pulsating output for the negative one-half cycle.
INPUT AND OUTPUT WAVEFORM OF BRIDGE RECTIFIER:
Note: the upper role is the A.C input voltage too the lower is the d.c pulsating output
AVERAGE OUTPUT VALUE OR Vdc:
Vdc=(1/π)∫Vm sinwt dwt
=(Vm/π)[-coswt]lim 0-π
Vdc=2Vm/π
Idc=2Im/π
RMS OUTPUT VOLTAGE:
Vrms=(1/π)√[∫Vm^2 sin^2(wt) dwt]
=(Vm/√2√π)√[∫1-cos2wt dwt]
=(Vm/√2√π)√[wt-(sin2wt/2)]
Vrms =Vm/√2
Irms=Im/√2
RIPPLE FACTOR:
τ=√((Vrms-Vdc)-1)
=√((π/2√2)^2-1)
τ = 0.483
EFFICIENCY:
Effiency is given equally the amount ability output to the amount ability input.
η=Vdc^2/Vrms^2
=8/π^2
η=81.2%
Tuf of amount moving ridge rectifier:
Tuf=power output /power rating of the transformer
=pac/Vrms.Irms
=8/√π^2
Tuf=0.8105
MATLAB STIMULATION CIRCUIT FOR BRIDGE RECTIFIER:
CONSTRUCTION:
The yoke rectifer has the iv pn junction connected is a yoke mode thence it is named equally the yoke rectifer. Then it consists of the transformer, resistive charge too a capacitor for filtering the output moving ridge purpose.
CIRCUIT DIAGRAM:
WORKING:
As of the other rectifiers it has 2 working cycles i.e the positive too negative one-half cycles.
(i)DURING THE POSITIVE HALF CYCLE:
During the positive one-half wheel the diodes i too iii are inwards frontward bias status too thence the conduction takes house via the loop D1RLD3 thence output is obtained equally pulsating output for positive one-half cycle.
(ii)DURING THE NEGATIVE HALF CYCLE:
During the negative one-half wheel the diodes 2 too 4 deport because of the frontward bias status too the diodes i too iii rest inwards off patch due to the opposite bias condition. In this representative the electrical flow flows inwards the loop D4RLD2 thence the output is obtained equally pulsating output for the negative one-half cycle.
INPUT AND OUTPUT WAVEFORM OF BRIDGE RECTIFIER:
Note: the upper role is the A.C input voltage too the lower is the d.c pulsating output
AVERAGE OUTPUT VALUE OR Vdc:
Vdc=(1/π)∫Vm sinwt dwt
=(Vm/π)[-coswt]lim 0-π
Vdc=2Vm/π
Idc=2Im/π
RMS OUTPUT VOLTAGE:
Vrms=(1/π)√[∫Vm^2 sin^2(wt) dwt]
=(Vm/√2√π)√[∫1-cos2wt dwt]
=(Vm/√2√π)√[wt-(sin2wt/2)]
Vrms =Vm/√2
Irms=Im/√2
RIPPLE FACTOR:
τ=√((Vrms-Vdc)-1)
=√((π/2√2)^2-1)
τ = 0.483
EFFICIENCY:
Effiency is given equally the amount ability output to the amount ability input.
η=Vdc^2/Vrms^2
=8/π^2
η=81.2%
Tuf of amount moving ridge rectifier:
Tuf=power output /power rating of the transformer
=pac/Vrms.Irms
=8/√π^2
Tuf=0.8105
MATLAB STIMULATION CIRCUIT FOR BRIDGE RECTIFIER:
0 Response to "Bridge Rectifier"
Posting Komentar